An=根号Sn+根号(Sn+1) 证明根号Sn是等差数列,求An通项公式
问题描述:
An=根号Sn+根号(Sn+1) 证明根号Sn是等差数列,求An通项公式
答
应该是 a(n+1)=[s(n)]^(1/2)+[s(n+1)]^(1/2)...s(n+1)-s(n)=a(n+1)=[s(n)]^(1/2)+[s(n+1)]^(1/2),{[s(n+1)]^(1/2)-[s(n)]^(1/2)}{[s(n+1)]^(1/2)+[s(n)]^(1/2)}=[s(n)]^(1/2)+[s(n+1)]^(1/2),[s(n+1)]^(1/2)-[s(n)]^...