已知实数x、y满足x2+4xy+4y2+x+2y-6=0,则x+2y的值为_.
问题描述:
已知实数x、y满足x2+4xy+4y2+x+2y-6=0,则x+2y的值为______.
答
x2+4xy+4y2+x+2y-6=0
(x+2y)2+(x+2y)-6=0
(x+2y+3)(x+2y-2)=0
∴x+2y+3=0,x+2y-2=0
即:x+2y=-3或2.