求不定积分:∫2x/[(1+x^4)arctan(x^2)] dx
问题描述:
求不定积分:∫2x/[(1+x^4)arctan(x^2)] dx
答
t=arctan(x^2),dt=2x/(1+x^4)dx,∫2x/[(1+x^4)arctan(x^2)] dx=∫1/tdt=InItI+c=InIarctan(x^2)I+c
求不定积分:∫2x/[(1+x^4)arctan(x^2)] dx
t=arctan(x^2),dt=2x/(1+x^4)dx,∫2x/[(1+x^4)arctan(x^2)] dx=∫1/tdt=InItI+c=InIarctan(x^2)I+c