实数X、y满足y=根号2-X+根号X-2+1,求X^2-y^2008的值

问题描述:

实数X、y满足y=根号2-X+根号X-2+1,求X^2-y^2008的值

y=根号2-X+根号X-2+1,
X=2,Y=1
X^2-Y^2008=4-1=3