SinA+SinB+SinC
问题描述：
SinA+SinB+SinC
答
在三角形ABC中证明(sinA)^2+(sinB)^2+(sinC)^2=2（1+cosAcosBcosC）由倍角公式：(sinA)^2+(sinB)^2+(sinC)^2=(1-cos2A)/2+(1-cos2B)/2+(1-cos2C)/2=3/2-1/2(cos2A+cos2B+cos2C) (对cos2A+cos2B用和差化积公式)=3/2-1...