(5x+4)/6-x=(x-3)/4+1

问题描述:

(5x+4)/6-x=(x-3)/4+1

(5x+4)(4+1)=(x-3)(6-x)
25x+20=-x^2+9x-18
x^2+16x+38=0
(x+)(x+)=0
x= -8+2√26 或-8+2√26