已知矩阵C=(1 2 3),B=(1 1/2 1/3),又A=B^T(B的转置矩阵)*C,求A^n
问题描述：
已知矩阵C=(1 2 3),B=(1 1/2 1/3),又A=B^T(B的转置矩阵)*C,求A^n
答
CB' = 1*1+2*(1/2)+3*(1/3) = 3.所以A^n = (B'C)(B'C)...(B'C) (n个连乘)= B'(CB')(CB')...(CB')C (乘法结合侓)= 3^(n-1) B'C=3^(n-1) 2*3^(n-1) 3^n3^(n-1)/2 3^(n-1) 3^n/23^(n-2) 2*3^(n-2) 3^(n-1)有问题消息我...