设集合S={A0,A1,A2,A3,A4,A5},在S上定义运算“⊕”为:Ai⊕Aj=Ak,其中k为i+j被4除的余数,i,j=0,1,2,3,4,5.则满足关系式(x⊕x)⊕A2=A0的x(x∈S)的个数为(  ) A.1 B.2 C.3

问题描述:

设集合S={A0,A1,A2,A3,A4,A5},在S上定义运算“⊕”为:Ai⊕Aj=Ak,其中k为i+j被4除的余数,i,j=0,1,2,3,4,5.则满足关系式(x⊕x)⊕A2=A0的x(x∈S)的个数为(  )
A. 1
B. 2
C. 3
D. 4

当x=A0时,(x⊕x)⊕A2=(A0⊕A0)⊕A2=A0⊕A2=A2≠A0当x=A1时,(x⊕x)⊕A2=(A1⊕A1)⊕A2=A2⊕A2=A4=A0当x=A2时,(x⊕x)⊕A2=(A2⊕A2)⊕A2=A0⊕A2=A2当x=A3时,(x⊕x)⊕A2=(A3⊕A3)⊕A2=A2⊕A2=A0=A0当...