设向量a1=(0 2 1),a2=(-1 0 3),a3=(1 2 0),则 -a1-1/2a2+3/2a3=多少

问题描述:

设向量a1=(0 2 1),a2=(-1 0 3),a3=(1 2 0),则 -a1-1/2a2+3/2a3=多少

(2,1,-2.5)

-a1-1/2a2+3/2a3=(2,1,-5/2)