2的n次方+2的n-1次方+·····+2+1
问题描述：
2的n次方+2的n-1次方+·····+2+1
答
=1×(2的(n+1)次方 -1) /(2-1)
=2的(n+1)次方 -1
答
==2的n+1次方-1
2^(n+1)-1
答
令s=2^n+2^(n-1)+.+2+1
2s=2^(n+1)+2^n+.+2^2+2^1
2s-s=2^(n+1)-1
s=2^(n+1)-1
答
=2^(n+1)-1