lim(x→1) (sin(x-1))/(x^2+x-1)的极限值,
问题描述:
lim(x→1) (sin(x-1))/(x^2+x-1)的极限值,
答
lim(x→1) (sin(x-1))=0
lim(x→1) (x^2+x-1)=1
所以
lim(x→1) (sin(x-1))/(x^2+x-1)=0