O是三角形ABC中一点,已知OA/OD+OB/OE+OC/OF=98.求OA/OD*OB/OE*OC/OF=
问题描述:
O是三角形ABC中一点,已知OA/OD+OB/OE+OC/OF=98.求OA/OD*OB/OE*OC/OF=
答
举特例,比如说是正三角形,O是内心,得到
OA/OD+OB/OE+OC/OF = OA/OD*OB/OE*OC/OF
所以OA/OD*OB/OE*OC/OF=98