如图所示,在△ABC中,AB=AC,M、N分别是AB、AC的中点,D、E为BC上的点,连接DN、EM,若AB=5cm,……如图所示,在△ABC中,AB=AC,M、N分别是AB、AC的中点,D、E为BC上的点,连接DN、EM,若AB=5cm,BC=8cm,DE=4cm,则图中阴影部分的面积为多少

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连接MN，作AF⊥BC于F．
∵AB=AC，
∴BF=CF=12BC=12×8=4，
在Rt△ABF中，AF=AB2-BF2=52-42=3，
∵M、N分别是AB，AC的中点，
∴MN是中位线，即平分三角形的高且MN=8÷2=4，
∴NM=12

BC=DE，
∴△MNO≌△EDO，O也是ME，ND的中点，
∴阴影三角形的高是12AF÷2=1.5÷2=0.75，
∴S阴影=4×0.75÷2=1.5．

连接MN,作AF垂直BC于F∵AB=AC∴BF=CF=1/2BC=1/2×8=4在Rt△ABF中,AF=根号下（AB平方-BF平方）=根号下（5平方-4平方）=3∵M、N分别是AB,AC的中点,∴MN是中位线,即平分三角形的高且MN=8÷2=4∴MN=DE∴△MNO≌△EDO,O也...