x/x-2=x²-8x+16/x²²-4x+4
问题描述：
x/x-2=x²-8x+16/x²²-4x+4
答
题目应该是：
x/(x-2) = (x²-8x+16)/(x²-4x+4)
原方程即：x/(x-2) = (x-4)² / (x-2)²
两边同时乘以 (x-2)²,得：x(x-2) = x²-8x+16
整理,得：x²-2x = x²-8x+16
即 -2x = -8x +16
解得 x = 8/3
经验算,x = 8/3 是原分式方程的解.