初2代数题（化简）a2 (1/b - 1/c ) + b2 (1/c - 1/a ) + c2(1/a - 1/b )_______________________________________________a (1/b - 1/c ) + b (1/c - 1/a ) + c (1/a - 1/b )*a2为a 的平方
问题描述：
初2代数题（化简）
a2 (1/b - 1/c ) + b2 (1/c - 1/a ) + c2(1/a - 1/b )
_______________________________________________
a (1/b - 1/c ) + b (1/c - 1/a ) + c (1/a - 1/b )
*a2为a 的平方
答
(a2+b2+c2)(1/b-1/c+1/c-1/a+1/a-1/b)= ___________________________________(a+b+c)(1/b-1/c+1/c-1/a+1/a-1/b)(a2+b2+c2)= ____________(a+b+c)(a+b+c)2= ____________(a+b+c)=1的平方=1