(2/3)(x的平方)+(1/3)x=2

问题描述:

(2/3)(x的平方)+(1/3)x=2

X=-2或x=3/2

(2/3)(x的平方)+(1/3)x=2
2x^2+x-6=0
(2x-3)(x+2)=0..........十字相乘法
解得 x=3/2或x=-2

(2/3)(x的平方)+(1/3)x=2
2x^2+x-6=0
(2x-3)(x+2)=0
x=3/2 或x= -2