奇函数f(x)定义域是(k,2k+3),则函数g(x)=(k+2)x^2+(k-1)x+3的递减区间是

问题描述:

奇函数f(x)定义域是(k,2k+3),则函数g(x)=(k+2)x^2+(k-1)x+3的递减区间是

奇函数定义域关于原点对称,k=-(2k+3),k=-1
g(x)=x^2-2x+3=(x-1)^2+2
减区间(-无穷,1)