求(sin(派-x)cos(3/2派-x)tanx)/(cos(2派-x)cot(x-派/2)sin(派/2-x))
问题描述:
求(sin(派-x)cos(3/2派-x)tanx)/(cos(2派-x)cot(x-派/2)sin(派/2-x))
答
原式
=(sinx•(-sinx)•tanx)/(cosx•(-tanx)•cosx)
=sin²x/cos²x
=tan²x