(1+sin2x-cos2x)/(1+sin2x+cosx)
问题描述:
(1+sin2x-cos2x)/(1+sin2x+cosx)
答
(1+sin2x-cos2x)/(1+sin2x+cosx)
=(2sin²x+2sinxcosx)/(2cos²x+2sinxcosx)
=sinx(sinx+cosx)/[cosx(cosx+sinx)]
=tanx