求不定积分∫x(x^2+1)^2dx求速打,
问题描述：
求不定积分∫x(x^2+1)^2dx
求速打,
答
∫x(x^2+1)^2dx
=1/2∫(x^2+1)^2d(x^2+1)
=1/2· 1/3·(x^2+1)^(2+1)+c
=1/6 (x^2+1)^3+c
答
∫x(x²+1)²dx=(1/2)∫(x²+1)²d(x²+1)
=(x²+1)³/6+C