已知数列an,a1=2,an+1(n+1是a右下角的注脚)=an+3n+2,则an=多少?
问题描述:
已知数列an,a1=2,an+1(n+1是a右下角的注脚)=an+3n+2,则an=多少?
1/2*n(3n+1).
答
∵a(n+1)=an+3n+2∴a(n+1)-an=3n+2则an-a(n-1)=3(n-1) + 2a(n-1)-a(n-2)=3(n-2) + 2a(n-2)-a(n-3)=3(n-3) + 2···a3 - a2 =3×2 + 2a2 - a1 =3×1 + 2全加,得an - a1 =3[1+2+3+……+(n-1)] + 2(n-1)an -...