1）4a^2+4a-4a^2b+b+1
问题描述：
1）4a^2+4a-4a^2b+b+1
2）ax^2+16ay^2-a-8axy
(3) a(a^2-a-1)+1
(4)ab(m^2+n^2)+mn(a^2+b^2)
答
1）4a^2+4a-4a^2b+b+1 ＝(4a^2+4a+1)-(4a^2b-b)=(2a+1)^2-b(2a+1)(2a-1)=(2a+1)〔2a+1-b(2a-1)〕=(2a+1)(2a+1-2ab+b)2）ax^2+16ay^2-a-8axy=a(x^2+16y^2-1-8xy)=a〔(x^2+16y^2-8xy)-1〕=a〔(x-4y)^2-1^2〕=a(x-4y+1)...