已知f(x)=ax5+bx3+cx+8,且f(-2)=10,则f(2)=(  ) A.-2 B.-6 C.6 D.8

问题描述:

已知f(x)=ax5+bx3+cx+8,且f(-2)=10,则f(2)=(  )
A. -2
B. -6
C. 6
D. 8

∵f(x)=ax5+bx3+cx+8
∴f(-2)=-32a-8b-2c+8=10,
∴32a+8b+2c=-2
则f(2)=32a+8b+2c+8=-2+8=6
故选C