计算:(1-1/22)(1-1/32)(1-1/42)…(1-1/20072)(1-1/20082).

问题描述:

计算:(1-

1
22
)(1-
1
32
)(1-
1
42
)…(1-
1
20072
)(1-
1
20082
).

原式=(1-

1
2
)(1+
1
2
)(1-
1
3
)(1+
1
3
)…(1-
1
2007
)(1+
1
2007
)(1-
1
2008
)(1+
1
2008

=(1-
1
2
)(1+
1
2008

=
2009
4016