设数列{an} 满足a1=0,an+an+1=2,则a2011的值为(  ) A.2 B.1 C.0 D.-2

问题描述:

设数列{an} 满足a1=0,an+an+1=2,则a2011的值为(  )
A. 2
B. 1
C. 0
D. -2

由已知得a2=2,a3=0,a4=2,a5=0
所以可知数列是周期为2的周期数列,
所以a2011=a1=0
故选C.