(2011•锦州三模)已知公差不为0的等差数列{an}满足a1,a3,a4成等比关系,Sn为{an}的前n项和,则S3−S2S5−S3的值为( ) A.2 B.3 C.15 D.不存在
问题描述:
(2011•锦州三模)已知公差不为0的等差数列{an}满足a1,a3,a4成等比关系,Sn为{an}的前n项和,则
的值为( )
S3−S2
S5−S3
A. 2
B. 3
C.
1 5
D. 不存在
答
因为{an}为等差数列,由a1,a3,a4成等比关系,得到a32=a1a4即(a1+2d)2=a1(a1+3d),
化简得d(a1+4d)=0由d≠0得到a1+4d=0,所以a1=-4d即a5=0,
则
=
S3−S2
S5−S3
=a3
a4+a5
=
a1+2d
a1+3d+0
=2−2d −d
故选A.