已知cosa=-3/5,pai

问题描述:

已知cosa=-3/5,pai

cosa=-3/5,paisina=-√(1-cos^2a)=-4/5
(sin(a/2)—cos(a/2))^2
=sin^2(a/2)-2sin(a/2)cos(a/2)+cos^2(a/2)
=1-2sina
=1-2*(-4/5)
=1+8/5
=13/5

α∈第三象限,所以sinα=-√(1-cos²α)=-4/5
所以(sin(a/2)—cos(a/2))^2 =sin²α/2 +cos²α/2 -2sinα/2cosα/2=1-sinα=1+4/5=9/5