3/(x-2)-4/(x-1)=1/(x-4)-2/(x-3) 大概是要用换元法的...
问题描述:
3/(x-2)-4/(x-1)=1/(x-4)-2/(x-3) 大概是要用换元法的...
答
3/(x-2)+2/(x-3)=4/(x-1)+1/(x-4) (5x-6)/(x^2-5x+6)=(5x-17)/(x^2-5x+4)(5x-6)(x^2-5x+4)=(5x-17)(x^2-5x+6)5x^3-31x^2-10x-24=5x^3-42x^2-75x-10211x^2+65x+78=0x=(-65±√793)/22已经知道答案了。。。于是就给最早回答的吧~~~