2012²-2011²-2010²-.-1²

问题描述:

2012²-2011²-2010²-.-1²

∵1²+2²+3²+.+n²=n(n+1)(2n+1)/6 (n是正整数)∴1²+2²+3²+.+2011²=2712931506故2012²-2011²-2010²-.-1²=2012²-2712931506=-2708883362.