2012²-2011²+2010²-2009²8······+2²-1²

问题描述:

2012²-2011²+2010²-2009²8······+2²-1²

=(2012+2011)*(2012-2011)+(2010+2009)*(2010-2009)+...+(2+1)*(2-1)
=2012+2011+2010+...+2+1
=[2012*(1+2012)]/2
=2013*1006
=2025078