两电阻并联,已知R1:R2=3:4,电流I1比I2多6A,求I1和I2
问题描述:
两电阻并联,已知R1:R2=3:4,电流I1比I2多6A,求I1和I2
答
两电阻并联,已知R1:R2=3:4,则I1:I2=4:3
又:I1-I2=6A
故有:I1=24A,I2=18A.