求由方程x^2+2xy-y^2=2x,所确定的隐函数y=y(x)的导数dy/dx
问题描述:
求由方程x^2+2xy-y^2=2x,所确定的隐函数y=y(x)的导数dy/dx
答
2x + 2y + 2xy' -2yy'=2
y'(x-y)=1-x-y
dy/dx = (1-x-y)/(x-y)