因式分解x^4-x^3y+4x^2y^2-3xy^3+3y^4
问题描述:
因式分解x^4-x^3y+4x^2y^2-3xy^3+3y^4
答
原式=x^4-x³y+x²y²+(3x²y²-3xy³+3y^4)=x²(x²-xy+y²)+3y²(x²-xy+y²)=(x²-xy+y²)(x²+3y²)
因式分解x^4-x^3y+4x^2y^2-3xy^3+3y^4
原式=x^4-x³y+x²y²+(3x²y²-3xy³+3y^4)=x²(x²-xy+y²)+3y²(x²-xy+y²)=(x²-xy+y²)(x²+3y²)