sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)
问题描述：
sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)
求化简过程.
答
原式=sin（x+π/3）+√3cos（x+π/3）+2sin（x-π/3）=2[1/2sin(x+π/3)+√3/2cos(x+π/3)]+2sin(x-π/3)=2sin(x+π/3+π/6)+2sin(x-π/3)=2[sin(x+π/2)+sin(x-π/3)]=2(cosx+√3/2sinx-1/2cosx)=2(√3/2sinx+1/2co...