数学题(1)38.5²-36.5²(2)(2x-3y-1)(2x+3y+1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
问题描述:
数学题(1)38.5²-36.5²(2)(2x-3y-1)(2x+3y+1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
抱歉是第一题38.5²-36.5² 第二题(2x-3y-1)(2x+3y+1)第三题(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)第四题2003^2-3001^2
答
1.38.5^2-36.5^2=(38.5+36.5)(38.5-36.5)=75*2=1502.(2x-3y-1)(2x+3y+1)=[2x-(3y+1)][2x+(3y+1)]=4x^2-(3y+1)^2=4x^2-(9y^2+6y+1)=4x^2-9y^2-6y-13.(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)=(1/2)(3-1)(3+1)(3^2+1)(3^4+...