正数数列{an}是公差不为零的等差数列,正项数列{bn}是等比数列,a1=b1,a3=b3,a7=b5,若a15=bm,求m的值.
问题描述:
正数数列{an}是公差不为零的等差数列,正项数列{bn}是等比数列,a1=b1,a3=b3,a7=b5,若a15=bm,求m的值.
答
令an=a1+(n-1)d,bn=b1•qn-1,
∵{an}为正数数列
∴d>0
令a1=b1=x
则由a3=b3,a7=b5得:
x+2d=x•q2,
x+6d=x•q4,
解得
q=
,d=
2
,x 2
∴由a15=bm,得
x+14d=x•qm-1
即2
=8,m−1 2
m=7.