设函数f(x)的导数为f‘(x),且f(x)=x²+2xf‘(1),则f‘(0)等于A.-2 B.-4 C.0 D.2
问题描述:
设函数f(x)的导数为f‘(x),且f(x)=x²+2xf‘(1),则f‘(0)等于
A.-2 B.-4 C.0 D.2
答
设函数f(x)的导数为f‘(x),且f(x)=x²+2xf‘(1),则f‘(0)等于
A.-2 B.-4 C.0 D.2