化简[tan(2π-α)sin(-2π-α)cos(6π-α)]/[cos(α-π)sin(5π-α)]
问题描述：
化简[tan(2π-α)sin(-2π-α)cos(6π-α)]/[cos(α-π)sin(5π-α)]
答
原式=[(-tana)(-sina)cosa]/[(-cosa)sina]
=(sina)^2/(-sinacosa)
=-tana
答
[tan(2π-α)sin(-2π-α)cos(6π-α)]/[cos(α-π)sin(5π-α)]=[tan(2π-α)sin(4π-2π-α)cos(4π+2π-α)]/[cos(π-α)sin(4π+π-α)]=[-tanα*sin(2π-α)cos(2π-α)]/[cos(π-α)sin(π-α)]=[-tanα*(-sin...