x^2-xy-4+2y因式分解

解
x²-xy-4+2y
=(x²-4)-(xy-2y)
=(x+2)(x-2)-y(x-2)
=(x-2)(x+2-y)
=(x-2)(x-y+2)

解:原式=(x^2-4)-(xy-2y)
=(x+2)(x-2)-y(x-2)
=(x-2)(x+2-y)

x²-xy-4+2y
=x²-4-xy+2y
=x²-2²-xy+2y
=(x+2)(x-2)-xy+2y
=(x+2)(x-2)-y(x-2)
=(x-2)[(x+2)-y]
=(x-2)(x+2-y)

x^2-xy-4+2y因式分解
=x²-4-y(x-2)
=(x-2)(x+2-y);
您好，很高兴为您解答，skyhunter002为您答疑解惑
如果本题有什么不明白可以追问，如果满意记得采纳
如果有其他问题请采纳本题后另发点击向我求助，答题不易，请谅解，谢谢。
祝学习进步

x^2-xy-4+2y因式分解
= x^2-4+2y-xy
= (x+2) (x-2) + y ( 2-x)
= (x+2) (x-2) - y (x-2)
= (x-y+2 ) (x-2 )

x^2-xy-4+2y
=x^2-4-xy+2y
=(x+2)(x-2)-y(x-2)
=(x-2)(x+2-y)