[2x(x^2y-Xy)+Xy(xy-x^2)]÷x^2y,其中x =2012,y=2013
问题描述：
[2x(x^2y-Xy)+Xy(xy-x^2)]÷x^2y,其中x =2012,y=2013
答
[2x(x^2y-xy^2)+xy(xy-x^2)]÷(x^2y)
=[2x*xy（x-y）+xy*x（y-x）]÷(x^2y)
=[2x^2*y(x-y)-x^2*y(x-y)]÷(x^2y)
=x^2*y(x-y)÷(x^2y)
=x-y
=2012-2013
=-1
答
[2x(x^2y-Xy)+Xy(xy-x^2)]÷x^2y,
=【2x^3y-2x^2y-x^2y^2-x^3y】÷x^2y
=[x^3y-2x^2y-x^2y^2]÷x^2y
=x-2-y
=x-y-2
=2012-2013-2
=-1-2
=-3