已知x-2y=3,x2-2xy+4y2=11.求下列各式的值: (1)xy; (2)x2y-2xy2.
问题描述:
已知x-2y=3,x2-2xy+4y2=11.求下列各式的值:
(1)xy;
(2)x2y-2xy2.
答
(1)x2-2xy+4y2=(x-2y)2+2xy=11,
将x-2y=3代入得:xy=1;
(2)∵xy=1,x-2y=3,
∴x2y-2xy2=xy(x-2y)=1×3=3.