先化简,再求值 -3(a²b-1)-2ab²-4,其中a=2010,b=1/2010

问题描述:

先化简,再求值 -3(a²b-1)-2ab²-4,其中a=2010,b=1/2010

化简=-3a²b+3-2ab²-4
=-ab(3a+2b)-1
将a=2010,b=1/2010代入
原式= -6030-2/2010-1
=-6031-1/1005

-3(a²b-1)-2ab²-4
=-3a²b+3-2ab²-4
=-ab(3a+2b)-1
=-(3a+2b+1)

-3(a²b-1)-2ab²-4
=-3a²b+3-2ab²-4
=-3a²b-2ab²-1
=-3x2010²x1/2010-2x2010x1/2010²-1
=-6030-1/1005-1
=-6031又1/1005