若S=11×3+13×5+…+1(2n-1)(2n+1),则S=______.
问题描述:
若S=
+1 1×3
+…+1 3×5
,则S=______. 1 (2n-1)(2n+1)
答
∵
=1 (2n-1)(2n+1)
(1 2
-1 2n-1
)1 2n+1
∴S=
+1 1×3
+…+1 3×5
=1 (2n-1)(2n+1)
(1-1 2
+1 3
-1 3
+…+1 5
-1 2n-1
)=1 2n+1
(1-1 2
)1 2n+1
∴S=
n 2n+1
故答案为:
n 2n+1
答案解析:利用裂项法,即可求出数列的和.
考试点:数列的求和.
知识点:本题考查数列求和,考查裂项法的运用,属于中档题.