如果(1/2a-x)^2=(1/4a^2)+(1/2y)*(x+1/9),求x和y值,分别是多少

问题描述:

如果(1/2a-x)^2=(1/4a^2)+(1/2y)*(x+1/9),求x和y值,分别是多少

(1/2a-x)^2=(1/4a^2)+(1/2y)*(x+1/9),1/4a^2-ax+x^2=1/4a^2+1/2xy+1/18y
题不对吧?