解方程组：（根号2）*X+2Y=根号2；X+【（根号2 ）+ 1）】*Y=（根号2 ）+3
问题描述：
解方程组：（根号2）*X+2Y=根号2；X+【（根号2 ）+ 1）】*Y=（根号2 ）+3
答
(√2)X+2Y= √2 -----(1)X+[(√2)+1]Y=√2 +3 -----(2)(2)式Ⅹ√2,得(√2)X+[2+(√2)]Y =2 +3√2 ----(3)(3)式-(2)式,得(√2)Y=2+2√2.所以Y=（√2）+2.X= -1-(2√2).方程组的解为：X= -1-(2√2)；Y=（√2）+2....