若x+y=2,xy=-4,求x2y+xy2+1的值
问题描述：
若x+y=2,xy=-4,求x2y+xy2+1的值
答
(x+y)(xy)=x^2y+xy^2=-8
原式=-7
若x+y=2,xy=-4,求x2y+xy2+1的值
(x+y)(xy)=x^2y+xy^2=-8
原式=-7