若f(sinx)=3-cos2x,则f(cosπ/6)=
问题描述：
若f(sinx)=3-cos2x,则f(cosπ/6)=
答
f(cosπ/6)= f(sinπ/2-π/6)=f(sinπ/3)=3-cos2*π/3=3+0.5=3.5
答
f(cosπ/6)
=f(sinπ/3)
=3-cos(2×π/3)
=3-(-1/2)
=7/2