根号3-1分之2+根号27-(根号3-1)零次方
问题描述:
根号3-1分之2+根号27-(根号3-1)零次方
答
根号3-1分之2+根号27-(根号3-1)零次方
=2(√3+1)/(√3+1)(√3-1)+3√3-1
=2(√3+1)/(3-1)+3√3-1
=√3+1+3√3-1
=4√3
答
2/(根号3-1) + 根号27-(根号3-1)零次方
= 2(根号3+1) /(3-1) + 3根号3 - 1
= 根号3+1 + 3根号3 - 1
= 4根号3