(π/6,π/4) cos2x 的定积分
问题描述:
(π/6,π/4) cos2x 的定积分
答
(π/6,π/4) cos2x
∫cos2xdx
=(1/2)sin2x (π/6,π/4)
=[(1/2)-(1/2)*(√3/2)]
=(2-√3)/4