化简求值:¼xy²+(2x²y-1)-(½xy²+3/2x²y),其中X=-1,y=2
问题描述:
化简求值:¼xy²+(2x²y-1)-(½xy²+3/2x²y),其中X=-1,y=2
答
:¼xy²+(2x²y-1)-(½xy²+3/2x²y)=¼xy²+2x²y-1-½xy²-3/2x²y=-¼xy²+1/2x²y-1=-¼×(-1)×4+1/2×1×2-1=1+1-1=1